(x-2)^2+20=0
(x-2)^2=-20
If you root both sides you will yield complex numbers (i, imaginary unit is such that i^2=-1),
x-2=20i
x=2+20i
and whenever x is a solution a complex conjugate x* is also a solution,
x*=2-20i
So the answer is A.
Hope this helps :)