The distance travelled during the given time can be found out by using the equations of motion.
The distance traveled during the time interval is "13810.8 m".
First, we will find the deceleration of the motorcycle by using the first equation of motion:
[tex]v_f=v_it+at\\\\[/tex]
where,
vi = initial velocity = (518 km/h)[tex](\frac{1\ h}{3600\ s})(\frac{1000\ m}{1\ km})[/tex] = 143.89 m/s
vf = final veocity = 60 % of 143.89 m/s = (0.6)(143.89 m/s) = 86.33 m/s
a = deceleration = ?
t =time interval = 2 min = 120 s
Therefore,
[tex]86.33\ m/s = 143.89\ m/s + a(120\ s)\\\\a = \frac{86.33\ m/s - 143.89\ m/s}{120\ s}[/tex]
a = -0.48 m/s²
Now, we will use the second equation of motion to find out the distance traveled (s):
[tex]s = v_it+\frac{1}{2}at^2\\\\s = (143.89\ m/s)(120\ s)+\frac{1}{2}(-0.48\ m/s^2)(120\ s)^2\\\\s = 17266.8\ m - 3456\ m[/tex]
s = 13810.8 m = 13.81 km
Learn more about the equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion.
