The average atomic mass for the mixture of Fe isotopes Fe-55 (15%) and Fe-56 (85%) is 55.85amu.
The average atomic mass (M) can be calculated as follows:
[tex] M = m_{1}\%_{1} + m_{2}\%_{2} [/tex]
Where:
m₁: is the mass of the isotope Fe-55 = 55
m₂: is the mass of the isotope Fe-56 = 56
%₁: is the abundance percent of the isotope Fe-55 = 15%
%₂: is the abundance percent of the isotope Fe-56 = 85%
Hence, the average atomic mass is:
[tex] M = 55*15\% + 56*85\% [/tex]
By changing the percent values to decimal ones, we have:
[tex] M = 55*0.15 + 56*0.85 = 55.85 amu [/tex]
Therefore, the average atomic mass of the mixture of isotopes is 55.85amu.
Learn more about isotopes here: https://brainly.com/question/860326?referrer=searchResults
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