The power of a factor of a dividend in the divisor must be less than or equal to its power in the dividend, for the dividend to be divisible by the divisor
The students that made incorrect statements are the 15th and 16th students
The reason the above values are correct are given as follows:
The given parameters are;
The number written on the board = A large multi digit number
The numbers given as the divisor of the large number are;
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31
The students said to give incorrect statements = Two students that spoke consecutively
Given that two consecutive numbers are incorrect, we have;
The numbers do not have multiples that are less than 31, therefore, the number cannot be any of 1 to 15
Also, we have;
3 × 6 = 18
4 × 5 = 20
3 × 7 = 21
2 × 11 = 22
4 × 6 = 24
2 × 13 = 26
4 × 7 = 28
5 × 6 = 30
However, we have 16 = 2⁴, which is the highest power of 2 in the range, 1
to 32 and likely to be larger than the required size of the even number
divisor, such that it will not divide the large number given the numbers of 2s
in 16, is larger than the number of 2s in the large number, which
gives the two possible numbers as 16 and 17
Therefore, the students that made incorrect statements are the 15th and 16th students
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