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A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s

Assuming No air resistance, what is the initial horizontal velocity of the cannonball.

A.)51.45 m/s
B.)147 m/s
C.)120 m/s
D.)9.8 m/s

Respuesta :

okpalawalter8

We have that Assuming No air resistance,the initial horizontal velocity of the cannonball is

[tex]V_h=84.3m/s[/tex]

From the question we are told that

A cannonball is shot from a cannon at a launch angle of 35 and an initial velocity of 147 m/s

Generally the equation for the horizontal velocity  is mathematically given as

[tex]V_h=Vsin\theta[/tex]

Therefore

[tex]V_h=147sin35[/tex]

[tex]V_h=84.3m/s[/tex]

Therefore

Assuming No air resistance,the initial horizontal velocity of the cannonball is

[tex]V_h=84.3m/s[/tex]

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