Write an expression that will cause the following code to print "equal" if the value of sensorreading is "close enough" to targetvalue. Otherwise, print "not equal". Hint: use epsilon value 0. 1.

Ex: if targetvalue is 0. 3333 and sensorreading is (1. 0/3. 0),

output is:.

Respuesta :

Expressions can be displayed using the print statement.

The expression in Python to carry out the task is:

if abs(sensorReading - targetValue) < 0.1:

    print("Equal")

else:

    print("Not Equal")

In the above code segment,

  • The absolute value is used to return the positive difference between sensorReading and targetValue
  • The if statement checks, if the difference is less than the epsilon value (0.1)
  • If yes, "Equal" is printed
  • If otherwise, "Not Equal" is printed

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