Answer:
5)0.53liters
6)1.634.6°c
Explanation:
[tex]using \: charles \: law \\ v1 \div t1 = v2 \div t2[/tex]
5) v1=25liters, t1=12000°c. v2=?, t2=250°c
v2=(250×25)/12000
v2=6250/12000
v2=0.52liters
6)v1=130,v2=85, t1=2500, t2=?
t2=(85×2500)/130
t2=212500/130
t2= 1634.6°c