caligirl005 caligirl005

15-09-2021
Physics

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A cannonball is shot from a cannon at a launch angle of 35oand an initial velocity of 147 m/s.The gravitational acceleration is −9.8 m/s2. Assuming NO air resistance, how long will it take the cannonball remain in the air.

Respuesta :

ravikirang118 ravikirang118

16-09-2021

Answer:

17.2

Explanation:

total time in air = 2usinx/g. (X=angle, u = initial velocity)

= (2×147×sin35)/9.8

=17.2s

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