The new volume of gas Y is 89.38 mL
From the question given above, the following data were obtained:
Initial volume (V₁) = 82.0 mL
Initial temperature (T₁) = 27.0 °C = 27 + 273 = 300 K
Final temperature (T₂) = 54.0 °C = 54 + 273 = 327 K
Pressure = 3 atm = constant
Final volume (V₂) =?
Since the pressure is constant, we shall determine the final volume of gas Y using the Charles' law equation as follow:
[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \\\\\frac{82}{300} = \frac{V_{2}}{327}[/tex]
Cross multiply
300 × V₂ = 82 × 327
300 × V₂ = 26814
Divide both side by 300
[tex]V_{2} = \frac{26814}{300}\\[/tex]
V₂ = 89.38 mL
Therefore, the new volume of gas Y is 89.38 mL
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