The concentration of potassium ion, K⁺ in the solution in mmol/L is 52 mmol/L
We'll begin by writing the balanced dissociation equation for K₂Cr₂O₇. This can be obtained as follow:
K₂Cr₂O₇(aq) —> 2K⁺(aq) + Cr₂O₇²¯(aq)
From the balanced equation above,
1 mole of K₂Cr₂O₇ produced 2 moles of K⁺
With the above information, we can obtain the concentration of potassium ion, K⁺ in the solution. This can be obtained as follow:
From the balanced equation above,
1 mole of K₂Cr₂O₇ produced 2 moles of K⁺.
Therefore,
26 mmol/L K₂Cr₂O₇ will produce = 2 × 26 = 52 mmol/L K⁺.
Thus, the concentration of potassium ion, K⁺ in the solution is 52 mmol/L
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