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A cheetah travelling initially at a speed of 25 m/s slows down
with a uniform acceleration of -5 m/s2. It takes the cheetah 5
seconds to stop. The cheetah travels meters within the 5
seconds. (in meters)

Respuesta :

  • Initial velocity=u=25m/s
  • Acceleration=a=-5m/s^2
  • Time=t=5s
  • Distance be s

[tex]\\ \bull\tt\dashrightarrow s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \bull\tt\dashrightarrow s=25(5)+\dfrac{1}{2}(-5)(5)^2[/tex]

[tex]\\ \bull\tt\dashrightarrow s=125+\dfrac{1}{2}(-125)[/tex]

[tex]\\ \bull\tt\dashrightarrow s=125-62.5[/tex]

[tex]\\ \bull\tt\dashrightarrow s=62.5m[/tex]

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