a. Velocity, V = 78.4 m/s
b. Displacement, S = 313.6 meters
Given the following data:
Acceleration due to gravity, a = 9.8 meter per seconds square.
a. To find the the stone’s velocity after 8.0 s, we would use the first equation of motion;
Mathematically, the first equation of motion is given by the formula;
[tex]V = U + at\\\\V = 0 + 9.8[/tex] × [tex]8[/tex]
Velocity, V = 78.4 m/s
b. To find the the stone’s displacement during this time, we would use the second equation of motion;
[tex]S = ut + \frac{1}{2}at^2\\\\S = 0(8) + \frac{1}{2}(9.8)(8)^2\\\\S = 0 + \frac{1}{2}(9.8)(64)[/tex]
[tex]S = 4.9[/tex] × [tex]64[/tex]
Displacement, S = 313.6 meters
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