The motion of the car in each interval of time are:
Δt(1) from 0 to 30 s and Δx(1) from 0 to 0.02 km
Δt(2) from 30 to 60 s and Δx(2) from 0.02 to 0.02 km
Δt(3) from 60 to 120 s and Δx(3) from 0.02 to 0.04 km
We know that car has a speed of 2 km/h in 30 seconds, we can use this information to find the distance in this interval of time.
Let's use the definition of speed.
[tex]v=\frac{\Delta x}{\Delta t}[/tex] (1)
Before finding the distance we need to convert the units of velocity, from km/h to km/s.
[tex]2\frac{km}{h}*\frac{1\: h}{3600\: s}=5.56*10^{-4}\: km[/tex]
Now we can use the equation (1) and solve it for Δx
[tex]\Delta x_{1}=v\Delta t[/tex]
[tex]\Delta x_{1}=5.56*10^{-4}*30[/tex]
[tex]\Delta x_{1}=0.02\: km[/tex]
Then, the car stops 30 seconds, and finally, it returns its travel at half its previous speed, which means at 1 km/h.
[tex]1\frac{km}{h}=2.78*10^{-4}\frac{km}{s}[/tex]
We calculate the final distance using [tex]t_{3} = 60 s[/tex] because the plot shows this value as the maximum interval of time.
[tex]\Delta x_{3}=2.78*10^{-4}*60=0.02\: s[/tex]
We can resume all the trajectories in the following list.
Δt(1) from 0 to 30 s and Δx(1) from 0 to 0.02 km
Δt(2) from 30 to 60 s and Δx(2) from 0.02 to 0.02 km
Δt(3) from 60 to 120 s and Δx(3) from 0.02 to 0.04 km
You can learn more about distance vs time plots here:
https://brainly.com/question/10824584
