The specific heat capacity is the heat required to raise the temperature of a unit mass of a substance by one degree Kelvin
The final temperature of the water and metal is 29.9°C
The specific heat capacity of the metal, is approximately 62.16 J/(kg·°C)
The reason the above values are correct are as follows:
The given parameters are;
The mass of the metal sample, m₁ = 34.526 g
The temperature to which the metal is heated, T₁ = 98.0°C
The mass of the water in the calorimeter, m₂ = 74.365 g
The temperature of the water, T₂ = 27.0°C
The temperature at which the water stabilized = 29.9°C
Required:
The final temperature of the water and metal
Solution:
From the question, the final temperature of the water and metal is 29.9°C
Required:
The heat capacity of the metal
Solution:
The heat gained by the water, q₂ = m₂·c·ΔT
ΔT = The temperature change of the water = (29.9 - 27) = 2.2
c = The specific heat capacity of water ≈ 4,200 J/(kg·°C)
∴ q₂ = 0.34526 × 4,200 × 2.2 = 3,190.2024
The heat loss by the steel, q₁ = m₁·c₁·ΔT
ΔT = 98.0°C - 29.9°C = 68.1°
c₁ = 3,190.2024/(68.1×0.75365) = 62.16 J/(kg·°C)
The specific heat capacity of the metal, c₁ = 62.16 J/(kg·°C)
Learn more about specific heat capacity here:
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