The next 3 terms of the geometric sequence will be 12, 24, and 48. And the next 3 terms of the arithmetic sequence will be 9, 12, and 15.
Let a be the first term and r be the common ratio.
Then the nth term of the geometric sequence is given as,
aₙ = a · (r)ⁿ⁻¹
Let a₁ be the first term and d be a common difference.
Then the nth term of the arithmetic sequence is given as,
aₙ = a₁ + (n - 1)d
A sequence starts 3, 6, ...
We have the first term is 3 and the common ratio is 2.
Then the next 3 terms of the geometric sequence will be
a₃ = 3 · (2)³⁻¹ = 12
a₄ = 3 · (2)⁴⁻¹ = 24
a₅ = 3 · (2)⁵⁻¹ = 48
The next 3 terms of the geometric sequence will be 12, 24, and 48.
We have the first term is 3 and the common difference is 3.
a₃ = 3 + (3 - 1) · 3 = 9
a₄ = 3 + (4 - 1) · 3 = 12
a₅ = 3 + (5 - 1) · 3 = 15
The next 3 terms of the arithmetic sequence will be 9, 12, and 15.
More about the geometric and arithmetic sequence link is given below.
https://brainly.com/question/22158345
#SPJ5
