Respuesta :
Answer:
27
Step-by-step explanation:
If p = 2q2 – 5 and q = 10 - 3r, find a. p when r equals 2 7. b. r when p equals 67. This problem has been solved!
Answer:
r = [tex]\frac{4}{3}[/tex]
Step-by-step explanation:
When p = 67 , then
2q² - 5 = 67 ( add 5 to both sides )
2q² = 72 ( divide both sides by 2 )
q² = 36 ( take square root of both sides )
q = [tex]\sqrt{36}[/tex] = 6
Then
6 = 10 - 3r ( subtract 10 from both sides )
- 4 = - 3r ( divide both sides by - 3 )
[tex]\frac{-4}{-3}[/tex] = r , that is
r = [tex]\frac{4}{3}[/tex]