1. A rock is initially launched from ground level vertically reaching its highest
point 4.2 seconds after being launched. Calculate the initial velocity of the
rock, to the nearest 100th, as the rock is launched. Calculate the maximum
height of the rock to the nearest 10th.
Explain and show all steps of your solution.

Respuesta :

the kinematics allows searching for the variables of movement of the body, finding the initial velocity and the height of the body

        v₀ = 41.16 m/s and y = 86.4 m

given parameters

  •  time to reach the highest point t = 4.2 s

to find

  • Initial velocity
  • The maximum height

The kinematics allows finding the relationships between the position, velocity and relationship of a body, for its use a reference system must be defined with respect to which to carry out the measurements. Let's set a rule system with the y-axis vertical and the upward direction as positive.

            v = v₀ - g t

Where v and v₀₀ are the velocity at the initial point e, respectively, g is the acerlation of gravity (g = 9.8 m / s²) and t is the time

         

At the highest point the velocity is zero

         0 = v₀ - g t

         v₀ = g t

         v₀ = 9.8 4.2

         v₀ = 41.16 m / s

To find the maximum height we use

        v² = vo² - 2 g y

where y is the height reached.

At the point of maximum height the velocity is zero

        0 = vo² - 2 g y

        y = [tex]\frac{v_o^2}{2g}[/tex]

        y = [tex]\frac{41.16^2}{2 \ 9.8 }[/tex]

        y = 86.44 m

using the criterion that the result is with a tenth

        y = 86.4 m

Using the kinematics relations we can find the initial velocity and the height of the body

         v₀ = 41.16 m / s and y = 86.4 m

learn more about kinematics  here:  

https://brainly.com/question/13390759