Answer:
» Answer: The third objective
[tex]{ \tt{h(x) = - 4x + 1}}[/tex]
• make x the subject:
[tex]{ \tt{h(x) - 1 = - 4x }} \\ \\ { \tt{x = \frac{h(x)}{ - 4} - \frac{1}{ - 4} }} \\ \\ { \tt{x = - \frac{h(x)}{4} + \frac{1}{4} }}[/tex]
• Therefore, f(x):
[tex] { \boxed{ \boxed{ \tt{ \: \: f(x) = - \frac{1}{4}x + \frac{1}{4} \: \: }}}}[/tex]
