Answer:
[tex] { \tt{ - x + 3y = - 6}} \\ { \tt{3y = x - 6}} \\ { \tt{y = \frac{1}{3}x - 2 }}[/tex]
• For parallel line, their gradients are the same:
→ m = ⅓
• From general equation of a line;
[tex]→ \: { \tt{y = mx + c}} \\ [/tex]
• For the point (9, -1):
[tex]→ \: { \tt{ - 1 = (9 \times \frac{1}{3} ) + c}} \\ \\→ \: { \tt{ - 1 = 3 + c}} \\ \\ → \: { \tt{c = - 4}}[/tex]
therefore:
[tex]→ \: { \boxed{ \tt{y = \frac{1}{3}x - 4 }}}[/tex]
