The average atomic mass of the mixture of argon containing 90% of 36Ar (35.968 amu) and 10% of 38Ar (37.962 amu) is 36.167 amu.
We have a mixture formed by 90% of 36Ar (atomic mass 35.968 amu) and 10% of 38Ar (atomic mass 37.962 amu). The average atomic mass (aam) of the mixture is a weighted average that considers the mass of each isotope ([tex]m_i[/tex]) and the abundance of each isotope in the mixture ([tex]ab_i[/tex]).
[tex]aam = \frac{\Sigma m_i \times ab_i }{100} = \frac{35.968amu \times 90 + 37.962amu \times 10}{100} = 36.167 amu[/tex]
The average atomic mass of the mixture of argon containing 90% of 36Ar (35.968 amu) and 10% of 38Ar (37.962 amu) is 36.167 amu.
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