Answer:
B
Step-by-step explanation:
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = - [tex]\frac{b}{2a}[/tex]
y = 3x² + 6x + 1 ← is in standard form
with a = 3 and b = 6 , then
[tex]x_{vertex}[/tex] = - [tex]\frac{6}{6}[/tex] = - 1
Substitute x = - 1 into y for corresponding y- coordinate
y = 3(- 1)² + 6(- 1) + 1
= 3(1) - 6 + 1
= 3 - 5
= - 2
vertex = (- 1, - 2 )
