Answer:
y = 1
Step-by-step explanation:
[tex] \frac{y + 3}{16} = \frac{2}{8} \\ = > y + 3 = \frac{2 \times 16}{8} \\ = > y + 3 = 2 \times 2 \\ = > y + 3 = 4 \\ = > y = 4 - 3 \\ = > y = 1[/tex]
