[tex]y = \frac{1}{2}x +2\\[/tex]
Equations of a line written in Slope-Intercept Form are usually written as [tex]y = mx +b[/tex] where [tex]b[/tex] is the constant and is also the [tex]y[/tex]-intercept. [tex]mx[/tex] is the [tex]x[/tex] term where [tex]m[/tex] is the slope. Also, the [tex]y[/tex] term is usually found at left side of the equation and it has to have [tex]1[/tex] as its coefficient.
From the given equation we can see the constant [tex]-8[/tex] is on the left side but only the [tex]y[/tex] term gets to be on the left side so let's add [tex]8[/tex] to both sides of the equation to cancel out [tex]-8[/tex].
[tex]4y -8 = 2x \\ 4y -8 +8 = 2x +8 \\ 4y = 2x +8[/tex]
We can also see that the [tex]y[/tex] term has a coefficient of [tex]4[/tex]. So let's divide both sides of the equation by [tex]4[/tex] to make the coefficient of the [tex]y[/tex] term to [tex]1[/tex]
[tex]4y = 2x +8 \\ \frac{4y}{4} = \frac{2x +8}{4} \\ y = \frac{1}{2}x +2[/tex]
