The 13-foot string is arranged into a rectangle. Let L denote the length of the rectangle,
and let W denote the width of the rectangle.
a. Write a formula for the width W as a function of the length L.
W=
b. Write a formula for the area A of the rectangle as a function of L
A=

Respuesta :

The expressions for the width, W, and area, A, of the rectangle in terms of L are:

  • W = [tex]\frac{13}{2}[/tex] - L
  • A = [tex]\frac{13L - L^{2} }{2}[/tex]

The expression for the perimeter of a rectangle is given as:

P = 2(L + W)

where L is its length and W its width

a. Given that the perimeter of the rectangle is 13 feet, then;

13 = 2(L + W)

divide through by 2

[tex]\frac{13}{2}[/tex] = L + W

So that;

W = [tex]\frac{13}{2}[/tex] - L

The required formula for the width as a function of L is: W = [tex]\frac{13}{2}[/tex] - L

b. Area of a rectangle can be expressed as;

A = L * W

substitute the expression for width in that of area to have

A = L * ( [tex]\frac{13}{2}[/tex] - L)

  = [tex]\frac{13}{2}[/tex]L - [tex]L^{2}[/tex]

A = [tex]\frac{13L - L^{2} }{2}[/tex]

The expression for the area A is: A = [tex]\frac{13L - L^{2} }{2}[/tex]

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