Answer:
Number 6:
• From the formula of force:
[tex]force = mass \times acceleration \\ { \boxed{f = ma}}[/tex]
• But we need to get the acceleration, from the first newtons equation of motion
[tex]v = u + at[/tex]
• v is the final velocity, but v is zero because the bullet came to rest.
• u is the initial velocity, u = 350 m/s
• a is the acceleration that we need
• t is the time, t = 0.0018 seconds.
» let's now substitute:
[tex]0 = 350 + (a \times 0.0018) \\ 0.0018a = - 350 \\a = - 194444.44 \\ { \underline{ \: \: |a| = 194444.44 \: m {s}^{ - 2} }}[/tex]
[ negative shows retârdation or deceleration or decrease in speed ]
• Therefore, let's find the force:
mass = 6g = (6/1000) kg = 0.006 kg
[tex]force = m \times |a| \\ f = 0.006 \times 194444.44 \\ { \underline{ \underline{ \: \: force = 1166.67 \: \: { \sf{newtons \: \: }}}}}[/tex]
