Answer:
[tex](z - 5)(z + 1) = 0[/tex]
• either (z - 5) or (z + 1) is 0
» For (z - 5)
[tex]z - 5 = 0 \\ { \underline{z = 5}}[/tex]
» For (z + 1)
[tex]z + 1 = 0 \\ { \underline{z = - 1}}[/tex]
Therefore:
[tex]{ \boxed{z _{1} = 5}} \: \: { \sf{and}} \: \: { \boxed{z_{2} = - 1}}[/tex]
