Answer:
• Let f(x) be m
[tex]m = \frac{2x + 1}{x} \\ \\ mx = 2x + 1 \\ \\ mx - 2x = 1 \\ \\ x(m - 2) = 1 \\ \\ x = \frac{1}{m - 2} [/tex]
Therefore:
[tex]{ \boxed{ {f}^{ - 1} (x) = \frac{1}{x - 2} }} \\ [/tex]
