Prove that……………….xjejj jrf
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Answer:
see explanation
Step-by-step explanation:
Using the rules of exponents
[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]
[tex]a^{\frac{m}{n} }[/tex] = [tex]\sqrt[n]{a^{m} }[/tex]
Given
[tex]y^{-\frac{a}{b} }[/tex]
= [tex]\frac{1}{y^{\frac{a}{b} } }[/tex]
= [tex]\frac{1}{\sqrt[b]{y^{a} } }[/tex]