Table a: y = x + 3
Table b: y = -x²
Table c: y = x² + 3
Table d: y = 3x - 1
For table a:
x = 1, 0, -4, 2, -2, -1
y = 4, 3, -1, 5, 1, 2
Each value of y is gotten by adding 3 to the corresponding value of x.
Therefore, the equation representing the data is y = x + 3
For table b:
x = -1, 3, 1, 0, -2, 2
y = -1, -9, -1, 0, -4, -4
Each value of y is gotten by finding the square of the corresponding value of x and negating the result
Therefore, the equation representing the data is y = -x²
For table c:
x = 3, -2, 1, 0, 2, -3
y = 12, 7, 4, 3, 7, 13
Each value of y is gotten by adding 3 to the square of the corresponding value of x
Therefore, the equation representing the data is y = x² + 3
For table d:
x = -3, 4, 2, -2, 0, -10
y = -10, 11, 5, -7, -1, -31
Each value of y is gotten by subtracting 1 from thrice the corresponding value of x
Therefore, the equation representing the data is y = 3x - 1
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