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Jason is pulling a box across the room. He is pulling with a force of 10 newtons and his arm is making a 74 angle with the horizontal, what is the vertical component of the force he is pulling with?

Respuesta :

Using vector concepts, it is found that the vertical component of the force is of 9.613 newtons.

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  • A vector (x,y) has horizontal component x and vertical component y.
  • The magnitude is [tex]M = \sqrt{x^2 + y^2}[/tex]
  • The components can be represented as function of the magnitude M and the angle between them [tex]\alpha[/tex], that is, [tex](M\cos{\alpha}, M\sin{\alpha}[/tex]

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  • The force is of 10 newtons, that is, M = 10.
  • Angle of 74 degrees, that is, [tex]\alpha = 74[/tex].
  • The vertical component is y, thus:

[tex]y = M\sin{\alpha} = 10\sin{74} = 9.613[/tex]

The vertical component of the force is of 9.613 newtons.

A similar problem is given at https://brainly.com/question/24606756

fichoh

The vertical component of the force Jason is pulling with is 9.613 N.

The vertical component of a force is given as :

[tex] F_{y} = Fsin\theta [/tex]

Force, F = 10 N

θ = 74°

Therefore,

[tex] F_{y} = 10 \times sin74 [/tex]

[tex] F_{y} = 10 \times 0.9612616 [/tex]

[tex] F_{y} = 9.612 N [/tex]

Therefore, the vertical component of the force is 9.613 N

Learn more : https://brainly.com/question/1454477?referrer=searchResults

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