A scientist is attempting to check the relative atomic masses on the periodic table. He works with three different compounds that contain only C and another compound. These are diatomic compounds with a formula of CX. He finds the following information. If he assumes the weight of C is 12 what is the weight of the other element (X1, X2, X3) and what is the identity of each unknown element?
Compound 1 Compound 2 Compound 3
Wt C Wt X 4.2 4.9 3.5 4.67 1.3 3.47

Respuesta :

The atomic mass of X₁ is 14 and the name of the element is Nitrogen.

The atomic mass of X₂ is 16 and the name of the element is Oxygen.

The atomic mass of X₃ is 32 and the name of the element is Sulfur.

The given parameters include:

                          weight C             weight X

Compound 1         4.2                     4.9

Compound 2         3.5                    4.67

Compound 3          1.3                     3.47

The atomic mass of the first compound (X₁) is calculated as follow;

let the total mass of X₁ and C = T

X₁ + C = T

[tex]\frac{weight \ of \ C}{total \ weight } \times total \ atomic \ mass = mass \ of \ C \\\\\frac{4.2}{(4.2 + 4.9)} \times T = 12\\\\4.2 T = 12(9.1)\\\\4.2T = 109.2\\\\T = \frac{109.2}{4.2} \\\\T = 26[/tex]

X₁ + C = T

X₁ + 12 = 26

X₁ = 26 - 12

X₁ = 14

The atomic mass of X₁ is 14 and the name of the element is Nitrogen.

The atomic mass of the second compound (X₂) is calculated as follow;

let the total mass = P

[tex]\frac{3.5}{(3.5+4.67)} \times P = 12\\\\3.5P = 12 (8.17)\\\\3.5P = 98.04\\\\P = \frac{98.04}{3.5} \\\\P = 28[/tex]

[tex]X_2 + C = P\\\\X_2 + 12 = 28\\\\X_2 = 28-12\\\\X_2 = 16[/tex]

The atomic mass of X₂ is 16 and the name of the element is Oxygen.

The atomic mass of the third compound (X₃) is calculated as follow;

Let the total mass = y

[tex]\frac{1.3}{(1.3+3.47)} \times y = 12\\\\1.3y = 12 (4.77)\\\\1.3y = 57.24\\\\y = \frac{57.24}{1.3} \\\\y = 44[/tex]

[tex]X_3 + C =y\\\\X_3 + 12 = 44\\\\X_3 = 44-12\\\\X_3 = 32[/tex]

The atomic mass of X₃ is 32 and the name of the element is Sulfur.

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