The edges of three squares are joined together to form a right triangle with legs of lengths r and s and a hypotenuse of length t. What must be true?
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The area of square T is equal to the sum of the areas of square R and square S.
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Explanation:
Recall that the pythagorean theorem says
a^2+b^2 = c^2
Visually this means if we had a square with side length 'a', then its area is a^2. The same goes for a square with side length b. Its area is b^2
So a^2+b^2 is the sum of those square areas. It being equal to c^2 tells us that adding the smaller square areas lead to the largest square area.
So that's why the areas of squares R and S add up to the area of square T.
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An example:
Let's say...
note how 3^2+4^2 = 9+16 = 25 and how 5^2 = 25. This shows 3^2+4^2 = 5^2
Answer: the area of the square t is equal to the sum of the areas of square r and square s
Step-by-step explanation:
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