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A projectile is thrown upward so that its distance above the ground after
t seconds is h = -16t2 + 608t.
After how many seconds does it reach its maximum height? (5 points)

Respuesta :

rspill6

Answer:  19 seconds

Step-by-step explanation:

The maximum height of this parabola will be when the slope of the line hits zero.  Take the first derivative and set it to 0, solve for t.

h = -16t2 + 608t

h' = -32t + 608

32t = 608

t = 19 sec

[The height at 19 seconds is h = -16(19)^2 + 608(19) = 5776 feet

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