Respuesta :
- 6min=1/10h=0.1h
- 3min=1/20h=0.05h
[tex]\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{Total\:Displacement}{Total\:Time}[/tex]
[tex]\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{10+3}{0.1+0.05}[/tex]
[tex]\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{13}{0.15}[/tex]
[tex]\\ \bull\tt\dashrightarrow Avg\:Speed=86.6km/h[/tex]
The average speed of the car traveling along the clear section of motorway and roadwork is 86.65km/h.
Speed
Speed is simply referred to as the distance traveled per unit of time.
It is expressed as;
S = total distance ÷ total time elapsed
Given the data in the question;
- Distance along clear motorway dc = 10km = 10000m
- Time elapsed along clear motorway; tc = 6.0min = 360s
- Distance along roadwork dr = 3km = 3000m
- Time elapsed along roadwork tr = 3.0min = 180s
To determine the average speed of the car, we substitute our given values into the expression above.
S = total distance ÷ total time elapsed
S = (dc + dr) ÷ ( tc + tr )
S = ( 10000m + 3000m ) ÷ ( 360s + 180s )
S = 13000m ÷ 540s
S = 24.07m/s
S = 86.65km/h
Therefore, the average speed of the car traveling along the clear section of motorway and roadwork is 86.65km/h.
Learn more about average speed here: https://brainly.com/question/9834403