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Answer:

771.15g of TiCl4

Explanation:

460 grams of sodium=20 mol

equation of the reaction is TiCl4+4NA=4NaCl+Ti

1 mol of titanium chlroide reacts with 4. that means there are 5 mols of titanium chloride

titanium chloride has a molar mass of 154.23 g.

mutiply that by 5 and we have 771.15 g

To react with 460 g of sodium, 949 g of titanium chloride are required.

Let's consider the following balanced equation.

TiCl₄ + 4 Na ⇒ Ti + 4 NaCl

We can calculate the mass of titanium chloride that reacts with 460 g of sodium considering the following relationships.

  • The molar mass of Na is 22.98 g/mol.
  • The molar ratio of TiCl₄ to Na is 1:4.
  • The molar mass of TiCl₄ is 189.68 g/mol.

[tex]460 g Na \times \frac{1molNa}{22.98gNa} \times \frac{1molTiCl_4}{4molNa} \times \frac{189.68gTiCl_4}{1molTiCl_4} = 949gTiCl_4[/tex]

To react with 460 g of sodium, 949 g of titanium chloride are required.

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