We have to find horizontal component of Mayosons velocity.
#a
[tex]\\ \tt\bull\leadsto V_x=vsin\theta[/tex]
[tex]\\ \tt\bull\leadsto V_x=2.5sin36[/tex]
[tex]\\ \tt\bull\leadsto V_x=2.5(0.58)[/tex]
[tex]\\ \tt\bull\leadsto V_x=1.45m/s[/tex]
#b
Here 2 vectors A=8 and B=2.5
[tex]\\ \tt\bull\leadsto \overrightarrow{R}[/tex]
[tex]\\ \tt\bull\leadsto \sqrt{A^2+B^2+2ABcos\Theta}[/tex]
[tex]\\ \tt\bull\leadsto \sqrt{8^2+2.5^2+2(8)(2.5)cos36}[/tex]
[tex]\\ \tt\bull\leadsto \sqrt{64+6.25+40(0.8)}[/tex]
[tex]\\ \tt\bull\leadsto \sqrt{70.25+32}[/tex]
[tex]\\ \tt\bull\leadsto \sqrt{102.25}[/tex]
[tex]\\ \tt\bull\leadsto 10.15m/s[/tex]
