Answer:
y=2 and x= 90
Step-by-step explanation:
13y+x+32y=180° [opposite angles of a cyclic quad]
Adding the like terms we get 45y+x=180°
Moving all the terms except x to the right side, we get x=180-45y. We will use this as the value of x(not an exact value)
2x-45y+x=180[opposite angles of a cyclic quad]
Adding the like terms we get 3x-45y=180°
Substitute the value of x into the equation 3x-45y=180°. You'll get something like 3(180°-45y)-45y=180°
Multiply the brackets out, you'll get 540°-135y-45y=180°. Adding the like terms we get 540-180y=180°
Moving all the other terms to one side and leaving - 180y we get: - 180y=180°-540°
Solving the right side we get - 180y= -360°
Dividing both sides of the equation by - 180, so that we are left with one variable(y), we get y=2
Substitute y=2 into the equation 3x-45y=180°. You'll get something like this: 3x-45(2)=180°
Multiplying out the brackets we get 3x-90°=180°
Moving all the terms to the other side so that we are left with one variable we get: 3x=180°+90°
Solving the right side we get 3x=270°.
Dividing out both sides of the equation by 3 we get x=90°
