The only true statement in the distribution is 261.
Given the following values :
125, 91, 261, 25, 155, 105, 195, 132, 110, 143, 121, 99, 167, 165, 160
Arranging the values in ascending order :
25, 91, 99, 105, 110, 121, 125, 132, 143, 155, 160, 165, 167, 195, 261
An outlier can be calculated thus :
Lower boundary = Q1 - (1.5 × IQR)
Upper boundary = Q3 + (1.5 × IQR)
Using a statistical calculator :
Lower quartile, Q1 = 105
Upper quartile, Q3 = 165
IQR = Q3 - Q1 = 165 - 105 = 60
Lower boundary = 105 - (1.5 × 60) = 15
Upper boundary = 165 + (1.5 × 60) = 255
Therefore, values lower than 15 or greater than 255 are outliers.
Hence, the outlier in the distribution is 261.
Learn more : https://brainly.com/question/24582786
