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Will mark BRAINLEIST
Four friends went out to eat one evening, and the mean price of their dinners was $10.54. If the prices of the first three meals were $9.62, $11.59, and $10.03, what was the cost of the fourth meal? SHOW YOUR WORK

Respuesta :

Answer:

[tex]mean = \frac{ \sum f(n)}{n} \\ [/tex]

n is number of terms

let cost of fourth meal be x :

[tex]10.54 = \frac{9.62 + 11.59 + 10.03 + x}{4} \\ \\ 10.54 = \frac{31.24 + x}{4} \\ \\ 31.24 + x = 4 \times 10.54 \\ \\ 31.24 + x = 42.16 \\ \\ x = 42.16 - 31.24 \\ \\ x = 10.92[/tex]

The cost of fourth meal is $10.92

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