Can someone please help me with this?
1. A circle with centre O. A,B, and C are points on the circumference. A tangent to

the circles passes through point A.

Given that angle BAC is 23° and angle ACB is 71°, find the size of angle ABC

You must show your workings provide reason and diagram

Respuesta :

The angle ABC is 86°.

By geometry, we know that triangles are formed by knowing three distinct points in a plane. In this case, the three points (A, B, C) are on the circumference. In addition, we know that the sum of the internal angles within a triangle equals 180°.

Then, the size of the angle ABC is found by the following expression:

[tex]\angle ABC = 180^{\circ} - \angle BAC - \angle ACB[/tex] (1)

If we know that [tex]\angle BAC = 23^{\circ}[/tex] and [tex]\angle ACB = 71^{\circ}[/tex], then the value of the angle ABC is:

[tex]\angle ABC = 180^{\circ} - 23^{\circ} - 71^{\circ}[/tex]

[tex]\angle ABC = 86^{\circ}[/tex]

The angle ABC is 86°.

We kindly invite to see this question on angles: https://brainly.com/question/18060525

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