Answer:
From the formula of force:
[tex]F = \frac{kAB}{ {r}^{2} } \\ [/tex]
since AB and k are constants:
[tex]F \: \alpha \: \frac{1}{ {r}^{2} } \\ \\ F = \frac{x}{ {r}^{2} } [/tex]
x is a constant of proportionality
• when force is 4N, separation distance is 1
[tex]4 = \frac{x}{1} \\ x = 4[/tex]
therefore, equation becomes
[tex]F = \frac{4}{ {r}^{2} } \\ [/tex]
when r is doubled, r becomes 2. find F:
[tex]F = \frac{4}{ {2}^{2} } \\ \\ F = \frac{4}{4} \\ \\ { \underline{force \: is \: 1N}}[/tex]
