#1
Here the basic reaction of C and O_2 occurs hence
[tex]\\ \sf\bull\longmapsto {C\atop 1mol}+{O_2\atop 1mol}={CO_2\atop 2mol}[/tex]
#2
First we have to find moles if Oxygen
- Mass=16g.
- Molar mass=16g/mol
[tex]\\ \sf\bull\longmapsto No\:of\:moles=\dfrac{Given\:mass}{molar\:mass}[/tex]
[tex]\\ \sf\bull\longmapsto \dfrac{16}{16}[/tex]
[tex]\\ \sf\bull\longmapsto 1mol[/tex]
Hence
It will be same like 1st one i. e 2mols of CO_2 will be produced .
#3
Now we already found moles in 16g of dioxygen
Hence
[tex]\\ \sf\bull\longmapsto {C\atop 2mol}+{O_2\atop 1mol}\longrightarrow {CO_2\atop 3mol}[/tex]
