Step-by-step explanation:
The pair of linear equation have
(1) unique solution if a₁/a₂ ≠ b₁/b₂
(2) infinite solution if a₁/a₂ = b₁/b₂ = c₁/c₂
(3) no solution if a₁/a₂ = b₁/b₂ ≠ c₁/c₂
Case (1) 3x-7y= 9 , -4x+5y = 1
or, 3x -7y -9 , -4x + 5y -1
3/-4≠ -7/5 ≠ -9/-1 satisfying a₁/a₂≠b₁/b≠c₁/c₂
∴ it has unique solution
- case (2) - 5x + y = 10 , -25x+ 5y = 50
- -5x + y -10, -25x +5y -50
1/5 = 1/5 = 1/5 satisfying a₁/a₂ = b₁/b₂ = c₁/c₂
since it has infinite solution
- case (3) y = 6x-2 , y = 6x-4
- or, y-6x+2 , y - 6x +4
1/1 = 1/1 ≠ 1/2 Satisfying a₁/a₂ = b₁/b₂ ≠ c₁ /c₂
since it has no solution .
So we have to arrange in order from least to greatest
so , case 3 < 1 < 2 Answer