Respuesta :
assumin a fraaction
remember some basic rules
x^-m=1/(x^m)
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
so
y^-5 really means 1/(y^5)
x^-3 means 1/(x^3)
we have
(1/y^5)/(1/x^3)
that equals
(x^3)/(y^5)
x=2
y=-4
(2^3)/((-4)^5)=8/-1024=-1/128
remember some basic rules
x^-m=1/(x^m)
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
so
y^-5 really means 1/(y^5)
x^-3 means 1/(x^3)
we have
(1/y^5)/(1/x^3)
that equals
(x^3)/(y^5)
x=2
y=-4
(2^3)/((-4)^5)=8/-1024=-1/128