Respuesta :
H=height
X=base
A=area
H=2b+4
A=1/2 bh
A=(1/2)(2b+4)b
(1/2)(2b+4)b<=168
Or
b^2+2b<=168
X=base
A=area
H=2b+4
A=1/2 bh
A=(1/2)(2b+4)b
(1/2)(2b+4)b<=168
Or
b^2+2b<=168
Answer:
(x² + 2x) < 168
Step-by-step explanation:
Let the height of the triangle is h in. and base is x in.
As per statement of the question, height of the triangle is 4 in. greater than twice twice of its base
The equation will be h = 2x + 4
Second statement is, the area of the triangle is not more than 168 in²
The inequality for this statement will be A < 168
Now we know area of a triangle A = [tex]\frac{1}{2}(\text{Base})({\text{height)}[/tex]
So A = [tex]\frac{1}{2}(x)(h)[/tex]
A = [tex]\frac{1}{2}(x)(2x+4)[/tex]
A = (x).(x + 2)
and A < 148
So inequality to find the length of x will be
x² + 2x < 168