Respuesta :
remember
i=√-1
complex numbers are written in form a+bi
so
113-√-68=
113-(√-1)(√(68)=
113-(i)(2√(17)=
113-2i√17
answer is B (what is that 't' doing there?)
i=√-1
complex numbers are written in form a+bi
so
113-√-68=
113-(√-1)(√(68)=
113-(i)(2√(17)=
113-2i√17
answer is B (what is that 't' doing there?)