Explanation:
Given mass of sugar = 1.202 g
Molar mass of the sugar , [tex]C_{12}H_{22}O_{11}[/tex] = 342.29 g/mol
a) Number of moles of sugar
[tex]\text{number of moles}=\frac{\text{given mass of sugar}}{\text{molar mass of sugar}}=\frac{1.202 g}{342.29g/mol}=0.0035 mol[/tex]
Number of moles of sugar in 1.202 grams is 0.0035 moles
b)Moles of each element in [tex]C_{12}H_{22}O_{11}[/tex]
In a molecular formula of sugar there are 12 carbon, 22 hydrogen and 11 oxygen atoms
Moles of an element in molecule =
number of atoms of that element in a molecular formula × number of moles of compound
Moles of carbon = 12 × 0.0035 = 0.042 moles
Similarly
Moles of hydrogen = 22 × 0.0035 = 0.077 moles
Moles of oxygen =11 × 0.0035 = 0.0385 moles
c) Number of atoms of each type in [tex]C_{12}H_{22}O_{11}[/tex]
[tex]\text{Number of atoms}=\text{number of moles of that atom in a molecular formula}\times \text{Avogadro number}[/tex]
Number of carbon atoms =[tex]0.042 mole\times 6.022 \times 10^{23}=2.52\times 10^{22} atoms[/tex]
Number of hydrogen =[tex]0.077mole\times 6.022 \times 10^{23}=4.63\times 10^{22} atoms[/tex]
Number of oxygen atoms = [tex]0.0385 mole\times 6.022 \times 10^{23}=2.31\times 10^{22} atoms[/tex]
