Answer:
(5,2)
Step-by-step explanation:
It is given that The coordinates of quadrilateral FGHJ are F(-5, -3), G(-3, 3), H(3, 5), and J(7, -1).
Now, the mid point is given as:
[tex]M=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})[/tex]
Then, the mid point of HJ having coordinates H(3, 5), and J(7, -1)is:
[tex]M=(\frac{3+7}{2},\frac{5+(-1)}{2})[/tex]
[tex]M=(\frac{3+7}{2},\frac{5-1}{2})[/tex]
[tex]M=(\frac{10}{2},\frac{4}{2})[/tex]
[tex]M=(5,2)[/tex]
Therefore, the mid point of HJ is (5,2).
