This problem is just what everybody likes to see:
A direct application of E=mc² !
If 0.100m kg of matter is converted to energy,
the quantity of energy is
E = m c²
= (0.1 kg) · (3 x 10⁸ m/s)²
= (0.1 kg) · (9 x 10¹⁶ m²/s²)
= (9 x 10¹⁵) (kg-m/s²)(m)
= (9 x 10¹⁵) (Newton)(m)
= (9 x 10¹⁵) Joules .
Thatsa lotta energy, Bub !
1 day = 86,400 seconds
Power = (energy) / (time)
= (9 x 10¹⁵ joules) / (86,400 seconds)
= 1.041 x 10¹¹ joules/sec
= almost exactly 1 gigawatt .
