Answer: Yes, he has enough ribbon.
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Explanation:
The volume is 296 cm^3 and the height of the box is 8 cm
The area of the top is 296/8 = 37 cm^2. I'm using the idea that
volume of box = (area of base)*(height)
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The area of the top is 37 cm^2. Apply the square root to get sqrt(37) = 6.08276 cm which is the approximate length of each side along the top. This only works if the top is a square.
Multiply this by 4 to get 4*6.08276 = 24.33104
The perimeter along the top is roughly 24.33 cm
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The next task we have to do is convert from inches to centimeters
Multiply by 2.54 to do this.
24 & 1/4 inches = 24 + 1/4 = 24 + 0.25 = 24.25 inches
24.25 * 2.54 = 61.595 cm
The measurement 24 & 1/4 inches converts to about 61.595 cm
This means Adam has about 61.595 cm of ribbon
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To recap, we found these two facts:
- The perimeter of the top is about 24.33 cm
- Adam has roughly 61.595 cm of ribbon
Since the amount he has (61.595) exceeds the perimeter (24.33), this means he does have enough ribbon.
In fact, he has enough ribbon to do 2 boxes because 61.595/24.33 = 2.53 approximately and that rounds down to 2. We don't round to 3 even though we're closer to it.
